Respuesta :

LammettHash
Looks like

[tex]\displaystyle g(x)=\int_4^xe^{2t^2-4t}\,\mathrm dt[/tex]

By the FTC,

[tex]\dfrac{\mathrm dg}{\mathrm dx}=e^{2x^2-4x}\cdot\dfrac{\mathrm dx}{\mathrm dx}=e^{2x^2-4x}[/tex]

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