Respuesta :

1 mole of NaHCO3 contains 84.007g,
Therefore,to get the number of mass of 6.33 mol we multiply the number of moles and the relative formula mass.
That is; 6.33 moles × 84.007 g =  531.764 g
Hence the mass of 6.33 moles of NaHCO3 is 531.764 grams

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