Respuesta :

Catya
assume the sample size is one to begin with and after double is two.

2 = 1*(1.039)^t
2 = (1.039)^t
log(2) = log(1.039^t)
log(2) = t*log(1.039)
log(2)/log(1.039) = t

18.12 hours = t

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