naymacruz naymacruz
  • 02-08-2017
  • Mathematics
contestada

Solve 5^x=81. 2
Round to the nearest ten-thousandth.

X≈????

Respuesta :

irspow
irspow irspow
  • 02-08-2017
Is that 5^x=81.2?

5^x=81.2  take the natural log of both sides

xln5=ln81.2  divide both sides by ln5

x=ln81.2/ln5

x≈2.7320  (to nearest ten-thousandth)

If you just meant 5^x=81, the process is the same

5^x=81  take the natural log of both sides

xln5=ln81  divide both sides by ln5

x=ln81/ln5

x≈2.7304  (to nearest ten-thousandth)


Answer Link

Otras preguntas

If you are good at math could you help me with this please
Write a rule for the linear function in the graph Plz help
Which is not a reason for migration in India today
PLEASE HELP IF YOU'RE FAMILIAR WITH THE PLAY "Our Town" Our Town can be classified as a modern ________ play. Mystery Miracle Morality Classic
"It's fine work. Monday bum Millay, Wednesday Whitman, Friday Faulkner, burn 'em to ashes, then bum the ashes. That's our official slogan." (Bradbury). Which of
PLEASE HELP ASAP MARKIN BRAINIEST!!! who is the intended audience of the speech city upon a hill JFK This is from Plato
Please help. I need it by tonight
Do you think defendants should have be found guilty beyond a reasonable doubt to be convicted? Or do you think a lesser burden of proof, like the preponderance
How was the city of Vicksburg captured ?
Almost done I swear thank u loll