Respuesta :
2C₂H₂ + 5O₂ = 4CO₂ + 2H₂O
m(CO₂)/{4M(CO₂)} = m(C₂H₂)/{2M(C₂H₂)}
m(CO₂)=2M(CO₂)m(C₂H₂)/M(C₂H₂)
m(CO₂)=2*44g/mol*38.9g/26g/mol = 131.7 g
131.7 grams of carbon dioxide would be formed
m(CO₂)/{4M(CO₂)} = m(C₂H₂)/{2M(C₂H₂)}
m(CO₂)=2M(CO₂)m(C₂H₂)/M(C₂H₂)
m(CO₂)=2*44g/mol*38.9g/26g/mol = 131.7 g
131.7 grams of carbon dioxide would be formed
