Respuesta :

Given:

[tex]8k-3>9k+10[/tex]

To solve for k:

Solving we get,

[tex]\begin{gathered} 8k-3>9k+10 \\ 8k-9k>10+3 \\ -k>13 \\ k<-13 \end{gathered}[/tex]

Hence, the answer is,

[tex]k<-13[/tex]

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