[tex]\begin{gathered} \text{surface area of the pyramid = 4 triangle area + }square\text{ area} \\ \text{triangle area=}\frac{5.1\cdot5.95}{2}=15.1725\operatorname{cm} \\ \\ squarearea=(5.1)^2=26.01\operatorname{cm} \\ \text{surface area of the pyramid = 4 }\cdot(15.1725)\text{ + }26.01 \\ \end{gathered}[/tex]
