Respuesta :

Given the following vector:

[tex]v=<-\sqrt{3},2\sqrt{3}>[/tex]

The magnitude of the vector will be as follows:

[tex]||v||=\sqrt{(-\sqrt{3})^2+(2\sqrt{3})^2}=\sqrt{3+12}=\sqrt{15}[/tex]

So, the answer will be option 2) ||v|| = √15