What is the solution to;
[tex]\begin{gathered} 4x+6\leq18 \\ \text{Subtract 6 from bothy sides} \\ 4x+6-6\leq18-6 \\ 4x\leq12 \\ \text{Divide both sides by 4} \\ \frac{4x}{4}\leq\frac{12}{4} \\ x\leq3 \end{gathered}[/tex]The first option is the correct answer
