Given:
[tex]64x^2-1=0[/tex]Required:
To solve the given equation by factoring method.
Explanation:
Consider
[tex]64x^2-1=0[/tex][tex]\begin{gathered} (8x)^2-1^2=0 \\ (8x+1)(8x-1)=0 \\ \\ 8x+1=0 \\ 8x=-1 \\ x=-\frac{1}{8} \end{gathered}[/tex]And
[tex]\begin{gathered} 8x-1=0 \\ 8x=1 \\ x=\frac{1}{8} \end{gathered}[/tex]Final Answer:
[tex]x=-\frac{1}{8},\frac{1}{8}[/tex]