Answer:
[tex]=\frac{4y^2}{x^2}[/tex]
Step-by-step explanation:
[tex]\frac{(8x^2y^3)}{(2x^4y)}[/tex]
[tex]=\frac{(8x^2y^3)}{(2x^4y)}\\[/tex]
[tex]=\frac{8y^2}{2x^2}[/tex]
I Hope This helps :)
