Respuesta :

loneguy

[tex]\text{Given that,}\\ \\\text{Volume,}~V= 57 mL = 0.057 L\\\\\text{Molar concentration,}~ S = 0.17 ~mol/L\\\\\text{Number of moles,} ~ n=?\\\\S = \dfrac{n}{V} \\\\\implies n = SV = 0.17\times 0.057 =0.00969 ~mol ~ HCl[/tex]