Answer:
D. -18x + 4
Step-by-step explanation:
[tex]-6(3x-\frac{2}{3})[/tex]
[tex]-6\cdot \:3x+6\cdot \frac{2}{3}[/tex]
[tex]-18x + 4[/tex]
[tex]{ \tt{ - 6(3x - \frac{2}{3}) }} \\ \\ = { \tt{ - 18x + ( \frac{2}{3} \times 6) }} \\ \\ = { \tt{ - 18x + (2 \times 2)}}\\ = { \boxed{ \tt{ - 18x + 4}}}[/tex]
