Answer:
(x-y+z)(x-y-z)
Given (x²-2xy+y²) - z²
= (x-y)² - z²
/* By algebraic identity
a²-2ab+b² = (a-b)² */
=[(x-y)+z][(x-y)-z]
/* a²-b² = (a+b)(a-b) */
= (x-y+z)(x-y-z)
Therefore,
(x²-2xy+y²)-z² =(x-y+z)(x-y-z)
Step-by-step explanation:
x
2
y
2
=x×x×y×y
xy
2
=x×y×y
h.c.f=xy
2
