Answer:
we have:
[tex]v = \frac{1}{3} \pi \: r {}^{2}h \\ \\ = > 60\pi = \frac{1}{3} \pi \: r {}^{2} h \\ \\ < = > 180 = r {}^{2} h[/tex]
=> r²h = 10.18 = 9.20 = 5.36 = 6.30 = 4.45 = 12.15
=> only r²h = 5.36 satisfy the problem
=> h = 5
h = 5 r = 6
h = 5 r = 6=> d = 12
