Respuesta :

TuChocolatito

Answer:

[tex] {}^{6} \sqrt{3a} = {}^{6} \sqrt{3a} \\ {}^{3} \sqrt{5a} = {}^{6} \sqrt{5 {}^{2} } a {}^{2} = {}^{6} \sqrt{25} \\ \sqrt{za} = {}^{6} \sqrt{2 {}^{3} } a {}^{3} = {}^{6} \sqrt{8a {}^{3} } [/tex]