Respuesta :

Answer:

[tex]3x^{2} -32=2x^{2} -4x\\3x^{2} -2x^{2} +4x-32=0\\x^{2} +4x-32=0\\x^{2} -4x+8x-32=0\\x(x-4)+8(x-4)=0\\(x-4)(x+8)=0\\x-4=0 \ or\ x+8=0\\x=4\ or\ x=-8[/tex]

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