Answer:
Step-by-step explanation:
We can use the distance formula derived from the Pythagorean theorem
D = [tex]\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}[/tex]
the two points given are
(0, 3) and (-2, -3)
[tex](x_2-x_1) = (0-(-2)) = 2\\(y_2-y_1) = (3-(-3)) = 6\\D = \sqrt{(2)^2 + (6)^2} \\D = \sqrt{4 + 36} \\D = \sqrt{40} = 6.324[/tex]
