Answer:
[tex] \huge \purple { \boxed{ C = \frac{5}{9} ( F - 32)}}[/tex]
Step-by-step explanation:
I the given problem, there should be 32 in place of 35.
[tex]F = \frac{9}{5} C + 32 \\ F - 32= \frac{9}{5} C \\ 5( F - 32)= 9 C \\ \frac{5}{9} ( F - 32)=C \\ \\ \huge \red{ \boxed{ C = \frac{5}{9} ( F - 32)}}[/tex]
