Answer:
The answer is A.
Step-by-step explanation:
You have to multiply by converting the second fraction into upside down :
[tex] \frac{4x + 1}{6x} \div \frac{x}{3x - 1} [/tex]
[tex] = \frac{4x + 1}{6x} \times \frac{3x - 1}{x} [/tex]
[tex] = \frac{(4x + 1)(3x - 1)}{x(6x)} [/tex]
[tex] = \frac{12 {x}^{2} - 4x + 3x - 1}{6 {x}^{2} } [/tex]
[tex] = \frac{12 {x}^{2} - x - 1 }{6 {x}^{2} } [/tex]
