Answer:
4y²−38y−20
Step-by-step explanation:
(y−10)(4y+2)
=(y+−10)(4y+2)
=(y)(4y)+(y)(2)+(−10)(4y)+(−10)(2)
=4y²+2y−40y−20
=4y²−38y−20
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[tex](y-10)(4y+2)\\ (a+b)(c+d)=ac+ad+bc+bd\\4y^2+2y-40y-20\\4y^2 -38y -20[/tex]
