Respuesta :

dalendrk
[tex]2v+3 > 4\dfrac{1}{3}\ \ \ \ \ |subtract\ 3\ from\ both\ sides\\\\2v > 1\dfrac{1}{3}\ \ \ \ |divide\ both\ sides\ by\ 2\\\\v > 1\dfrac{1}{3}:2\\\\v > \dfrac{4}{3}\cdot\dfrac{1}{2}\\\\\boxed{v > \frac{2}{3}}[/tex]