Answer:
[tex]$\frac{9^{32}}{17^{28}}$[/tex]
Step-by-step explanation:
We got:
[tex]$(\frac{9^8}{17^7} )^4$[/tex]
[tex]$\frac{\left(9^8\right)^4}{\left(17^7\right)^4}$[/tex]
