Respuesta :

dalendrk
[tex]6\tan3x=6\ \ \ \ |divide\ both\ sides\ by\ 6\\\\\tan3x=1`\\\\3x=\dfrac{\pi}{4}+k\pi\ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=\dfrac{\pi}{12}+\dfrac{k\pi}{3}\ where\ k\in\mathbb{Z}}[/tex]