Answer:
D = ]-∞ , -1/2[ U ]-1/2 , 3[ U ]3 , +∞[
Step-by-step explanation:
hello :
f(x) = x/(2x²-5x-3)
f exist for : 2x²-5x-3 ≠ 0
2x²-5x-3 = 0
∆ = b² -4ac a=2 and b= -5 and c= -3
∆ = (-5)² - 4(2)(-3) = 49 = 7²
X1 = (-b-√∆ )/2a = (5-7)/4 = -1/2
X2 = (-b+√∆ )/2a = (5+7)/4 = 3
the domain is : D = ]-∞ , -1/2[ U ]-1/2 , 3[ U ]3 , +∞[
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