Answer:
[tex]a_{n} = 6n-1[/tex]
Step-by-step explanation:
The formula is: [tex]a_{n}= a_{1}+d (n-1)[/tex]
where n is every [tex]n^{th}[/tex] term
substitute in [tex]a_{1}[/tex] which is 5 and d which equals 6.
d=6 because that's the difference between each number.
so [tex]a_{n} = 5 +(6)(n-1)[/tex]
[tex]a_{n} = 5 + 6n +6[/tex]
[tex]a_{n} = 6n-1[/tex]
