Answer:
[H⁺] = 2.0 × 10⁻¹² M
Explanation:
Given data:
Concentration of KOH = 0.005M
H⁺ = ?
Solution:
pOH = -log[ OH⁻]
pOH = -log[0.005]
pOH = 2.3
pH + pOH = 14
14 - pOH = pH
pH = 14 - 2.3
pH = 11.7
pH = -log[H⁺]
11.7 = -log[H⁺]
[H⁺] = Antilog (-11.7)
