we can use
each interior angle formula of any regular polygons
[tex] \theta=\frac{180(n-2)}{n} [/tex]
where
n is number of sides
theta is angle
we are given
[tex] \theta=157.5 [/tex]
now, we can plug it
[tex] 157.5=\frac{180(n-2)}{n} [/tex]
now, we can solve for n
[tex] 1575n=1800\left(n-2\right) [/tex]
[tex] n=16 [/tex]
so, option-C......Answer
